Step 1: Use identity for \( \sin 2\theta \).
\[
\sin 2\theta = 2 \sin \theta \cos \theta
\]
Step 2: Use triangle to find \( \sin \theta \) and \( \cos \theta \).
Given: \( \tan \theta = \frac{3}{4} \Rightarrow \frac{\text{opposite}}{\text{adjacent}} \).
Let opposite = 3, adjacent = 4. Then hypotenuse:
\[
\text{hypotenuse} = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5
\]
\[
\sin \theta = \frac{3}{5}, \quad \cos \theta = \frac{4}{5}
\]
Step 3: Plug values into identity.
\[
\sin 2\theta = 2 \cdot \frac{3}{5} \cdot \frac{4}{5} = \frac{24}{25}
\]