Question

If ‘PENCIL’ is coded as ‘QFODJM’, then ‘MARKER’ will be coded as:

• A. NBSLFS
• B. NBSJFS
• C. NSBLFS
• D. NBTLFS

Hint:

To verify your choice quickly under exam pressure, test just the first few and the very last letters of the word: $\text{M} \rightarrow \text{N}$, $\text{A} \rightarrow \text{B}$, and $\text{R} \rightarrow \text{S}$. This means the word must start with "NB..." and end with "...S". This immediately eliminates option (d)!

Answer 1

The Correct Option is A

Step 1: Understanding the Concept:
Letter coding questions rely on systematic transformations along the alphabetical index. To establish the code layout, we match every character of the given example word to its encrypted counterpart in the same position and measure the distance shifted.

Step 2: Key Formula or Approach:
Analyze the alphabetic stepping rule of each character element: $$\text{Letter}_{\text{Code}} = \text{Letter}_{\text{Original}} + n$$ Determine the index shift step value ($n$), then map out the target word using the identical shift rule.

Step 3: Detailed Explanation:
Let's inspect the letter shifts inside the reference pattern PENCIL $\rightarrow$ QFODJM: $\text{P} \xrightarrow{+1} \text{Q}$ $\text{E} \xrightarrow{+1} \text{F}$ $\text{N} \xrightarrow{+1} \text{O}$ $\text{C} \xrightarrow{+1} \text{D}$ $\text{I} \xrightarrow{+1} \text{J}$ $\text{L} \xrightarrow{+1} \text{M}$ The coding pattern shifts every letter forward by exactly one position ($+1$ linear progression). Now, execute this identical $+1$ shift rule across all letters of the word MARKER: $\text{M} \xrightarrow{+1} \text{N}$ $\text{A} \xrightarrow{+1} \text{B}$ $\text{R} \xrightarrow{+1} \text{S}$ $\text{K} \xrightarrow{+1} \text{L}$ $\text{E} \xrightarrow{+1} \text{F}$ $\text{R} \xrightarrow{+1} \text{S}$ Combining the resulting sequence of characters yields the coded word NBSLFS. This matches the text given in option (a).

Step 4: Final Answer:
The code for "MARKER" is NBSLFS.