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if m things are distributed among a men and b wome
Question:
If \(m\) things are distributed among \(a\) men and \(b\) women, then the chance that the number of things received by men is odd is:
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Odd-even separation uses \((x+y)^n \pm (x-y)^n\).
MET - 2020
MET
Updated On:
Apr 16, 2026
\(\frac{(b-a)^m - (b+a)^m}{2(b+a)^m}\)
\(\frac{(b+a)^m - (b-a)^m}{2(b+a)^m}\)
\(\frac{(b+a)^m - (b-a)^m}{(b+a)^m}\)
None of these
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The Correct Option is
B
Solution and Explanation
Concept:
Each object has \((a+b)\) choices.
Step 1:
Total ways.
\[ (a+b)^m \]
Step 2:
Use binomial expansion.
Number of ways men get odd objects: \[ \frac{(a+b)^m - (b-a)^m}{2} \]
Step 3:
Probability.
\[ \frac{(a+b)^m - (b-a)^m}{2(a+b)^m} \]
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