We are given two logarithmic equations and need to find the sum of a and b. Let's solve them step-by-step.
log2(5+log3a)=3
This implies:
23 = 5 + log3a
8 = 5 + log3a
log3a = 8 - 5 = 3
Therefore, a = 33 = 27
log5(4a+12+log2b)=3
This implies:
53 = 4a + 12 + log2b
125 = 4a + 12 + log2b
Using value of a from step 1:
125 = 4(27) + 12 + log2b
125 = 108 + 12 + log2b
125 = 120 + log2b
log2b = 125 - 120 = 5
Therefore, b = 25 = 32
a + b = 27 + 32 = 59
Thus, the value of a + b is 59.
Consider two distinct positive numbers \( m, n \) with \( m > n \). Let \[ x = n^{\log_n m}, \quad y = m^{\log_m n}. \] The relation between \( x \) and \( y \) is -
If \[ \log_{p^{1/2}} y \times \log_{y^{1/2}} p = 16, \] then find the value of the given expression.