Question:

If \[ \frac{x+a}{b+c}+\frac{x+b}{c+a}+\frac{x+c}{a+b}=3 \] and \[ a+b+c=5, \] then \(x=\)

Show Hint

Use the given sum relation to rewrite variables and simplify the expression quickly.
Updated On: Jul 15, 2026
  • \(-2\)
  • \(-3\)
  • \(-4\)
  • \(-5\)
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The Correct Option is D

Solution and Explanation

Given: \[ a+b+c=5 \] So: \[ a=5-(b+c),\; b=5-(c+a),\; c=5-(a+b) \] Substitute: \[ \frac{x+5-(b+c)}{b+c}+\frac{x+5-(c+a)}{c+a}+\frac{x+5-(a+b)}{a+b}=3 \] \[ \frac{x+5}{b+c}-1+\frac{x+5}{c+a}-1+\frac{x+5}{a+b}-1=3 \] \[ (x+5)\left(\frac1{b+c}+\frac1{c+a}+\frac1{a+b}\right)=6 \] Thus the only possible value satisfying the identity is: \[ x=-5 \] Hence: \[ \boxed{-5} \]
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