The capacitors are in parallel with the battery, so each capacitor has the same voltage, $V = 240$ V.
Capacitances: 2 $\mu$F, 5 $\mu$F, 4 $\mu$F, 1 $\mu$F, 12 $\mu$F.
For the 1 $\mu$F capacitor, charge $Q = C V = 1 \times 10^{-6} \times 240 = 240 \times 10^{-6}$ C = 240 $\mu$C.
In parallel, the voltage across each capacitor is the same as the battery voltage, so no need to calculate equivalent capacitance for this part.