Question:

If $f(x)=\begin{cases}\frac{x}{|x|}when~x\ne0\\ |x|when~x=0\end{cases}$ is a real valued function, then}

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Discontinuity automatically implies non-differentiability.
Updated On: Jun 22, 2026
  • f is continuous but not differentiable at $x=0$
  • f is both continuous and differentiable at $x=0$
  • f is not defined at $x=0$
  • f is neither continuous nor differentiable at $x=0$ \bigskip
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The Correct Option is D

Solution and Explanation

Concept: Check continuity first, then differentiability.

Step 1:
Behavior for $x>0$.
\[ f(x)=1 \]

Step 2:
Behavior for $x<0$.
\[ f(x)=-1 \]

Step 3:
Value at $x=0$.
\[ f(0)=0 \]

Step 4:
Check left and right limits.
\[ lim_{x\to 0^-}f(x)=-1,\quad lim_{x\to 0^+}f(x)=1 \] Since LHL $\ne$ RHL: function is discontinuous.

Step 5:
Conclude differentiability.
Discontinuous $\Rightarrow$ not differentiable.
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