\(f(x)=\frac{5x+2 }{ 3x-5}\) and \(g(x)=x^2-2x-1\)Substituting, \(f(3)=\frac{(5×3+2)}{(3×3−5)}=\frac{17}{4}\)
\(f(f(3))=\frac{(5×(\frac{17}{4})+2)}{(3×(\frac{17}{4})−5)}=3\)\(g(f(f(3)))=g(3)=9−6−1=2.\)