Question:
If $f_{m}$ is a modulating frequency and $f_{c}$ is carrier wave frequency, then Bandwidth in Amplitude Modulated wave is
If $f_{m}$ is a modulating frequency and $f_{c}$ is carrier wave frequency, then Bandwidth in Amplitude Modulated wave is
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Bandwidth of an AM signal is always independent of the carrier frequency value and equals exactly twice the message frequency: $\text{BW} = 2 \times f_{\text{message}}$.
Updated On: Jun 3, 2026
- $2f_{c}$
- $f_{c} + f_{m}$
- $2f_{m}$
- $\frac{(f_{c} + f_{m})}{2}$
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The Correct Option is C
Solution and Explanation
Step 1: Concept
In Amplitude Modulation (AM), when a carrier wave of frequency $f_{c}$ is modulated by a signal of frequency $f_{m}$, sidebands are created.
Step 2: Meaning
The modulation process produces two prominent sideband frequencies: the Upper Sideband ($\text{USB} = f_{c} + f_{m}$) and the Lower Sideband ($\text{LSB} = f_{c} - f_{m}$).
Step 3: Analysis
The bandwidth (BW) of a modulated signal is defined as the difference between the maximum and minimum frequencies contained within the wave: $$\text{BW} = \text{USB} - \text{LSB} = (f_{c} + f_{m}) - (f_{c} - f_{m}) = 2f_{m}$$
Step 4: Conclusion
Therefore, the bandwidth of the amplitude modulated wave is exactly twice the modulating frequency ($2f_{m}$).
Final Answer: (C)
In Amplitude Modulation (AM), when a carrier wave of frequency $f_{c}$ is modulated by a signal of frequency $f_{m}$, sidebands are created.
Step 2: Meaning
The modulation process produces two prominent sideband frequencies: the Upper Sideband ($\text{USB} = f_{c} + f_{m}$) and the Lower Sideband ($\text{LSB} = f_{c} - f_{m}$).
Step 3: Analysis
The bandwidth (BW) of a modulated signal is defined as the difference between the maximum and minimum frequencies contained within the wave: $$\text{BW} = \text{USB} - \text{LSB} = (f_{c} + f_{m}) - (f_{c} - f_{m}) = 2f_{m}$$
Step 4: Conclusion
Therefore, the bandwidth of the amplitude modulated wave is exactly twice the modulating frequency ($2f_{m}$).
Final Answer: (C)
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