Question:

If \( f \) is the inverse function of \( g \) and \( g'(x) = \dfrac{1{1 + x^n} \), then the value of \( f'(x) \) is:}

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Inverse derivative formula: \[ f'(x) = \frac{1}{g'(f(x))} \] Always substitute the inverse inside derivative.
  • \( 1 + (f(x))^n \)
  • \( 1 - (f(x))^n \)
  • \( \{1 + f(x)\}^n \)
  • \( (f(x))^n \)
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The Correct Option is A

Solution and Explanation

Concept: Derivative of inverse function: \[ f'(x) = \frac{1}{g'(f(x))} \] Step 1: {\color{red}Apply inverse derivative rule.} Given: \[ g'(x) = \frac{1}{1 + x^n} \] So: \[ f'(x) = \frac{1}{g'(f(x))} \] Step 2: {\color{red}Substitute.} \[ g'(f(x)) = \frac{1}{1 + (f(x))^n} \] Hence: \[ f'(x) = 1 + (f(x))^n \]
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