Question:

If \[ \csc\theta+\cot\theta=5 \] then \[ 11+12\tan\theta= \]

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For \(\csc\theta \pm \cot\theta\), always use the product identity to simplify quickly.
Updated On: Jul 15, 2026
  • \(6\)
  • \(9\)
  • \(14\)
  • \(16\)
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The Correct Option is D

Solution and Explanation

Given: \[ \csc\theta+\cot\theta=5 \] Using identity: \[ (\csc\theta+\cot\theta)(\csc\theta-\cot\theta)=1 \] So: \[ \csc\theta-\cot\theta=\frac15 \] Add: \[ 2\csc\theta=5+\frac15=\frac{26}{5} \Rightarrow \csc\theta=\frac{13}{5} \] Subtract: \[ 2\cot\theta=5-\frac15=\frac{24}{5} \Rightarrow \cot\theta=\frac{12}{5} \] Thus: \[ \tan\theta=\frac{5}{12} \] Now: \[ 11+12\tan\theta=11+12\left(\frac{5}{12}\right)=11+5=16 \] Hence, \[ \boxed{16} \]
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