If bromine atom is available in the form of, say, two isotopes \(^{79}Br_{35}\) (49.7%) and \(^{81} Br_{35}\) (50.3%), calculate the average atomic mass of bromine atom.
It is given that two isotopes of bromine are \(^{79}Br_{35}\) (49.7%) and \(^{81} Br_{35}\) (50.3%).
Then, the average atomic mass of bromine atom is = 7\(9 \times \frac{49.7}{100} + 81 \times \frac{ 50.3}{100}\)
= \(\frac{2926.3}{100} + \frac{4074.3}{100}\)
= \(\frac{8000.6}{100}\)
= \(80.006\) u
Length (in hours) | Number of lamps |
|---|---|
300 − 400 | 14 |
400 − 500 | 56 |
500 − 600 | 60 |
600 − 700 | 86 |
700 − 800 | 74 |
800 − 900 | 62 |
900 − 1000 | 48 |
(i) Represent the given information with the help of a histogram.
(ii) How many lamps have a lifetime of more than 700 hours?
Why was Santosh sent to the local school?