Step 1: Understanding the problem.
We are tossing a coin three times and need the probability that NO two successive tosses show the same face. The possible sequences of tosses are: - HTH, THT (both have no successive tosses with the same face).
Step 2: Analyzing the total number of possible outcomes.
The total number of possible outcomes for three tosses of a coin is \( 2^3 = 8 \). The possible sequences are: HTH, THT, HHH, TTT, HHT, HTT, THH, TTH.
Step 3: Calculating favorable outcomes.
The favorable outcomes are HTH and THT. Therefore, the number of favorable outcomes is 2.
Step 4: Calculating probability.
The probability is the ratio of favorable outcomes to total outcomes: \[ P = \frac{2}{8} = 0.25. \]
Step 5: Conclusion.
The correct answer is (A) 0.25.
| $X_i$ | 5 | 6 | 8 | 10 |
| $F_i$ | 8 | 10 | 10 | 12 |
| X | 0 | 1 | 2 | 3 | 4 | 5 |
| P(X) | 0 | K | 2K | 3K | 4K | 5K |
| $X_i$ | 5 | 6 | 8 | 10 |
| $F_i$ | 8 | 10 | 10 | 12 |
| X | 0 | 1 | 2 | 3 | 4 | 5 |
| P(X) | 0 | K | 2K | 3K | 4K | 5K |