Question:

If \(A = \begin{bmatrix} 0\;\;-1\\1\;\;0 \end{bmatrix}\), then which one of the following statements is not correct?

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Compute \(A^2\); it equals \(-I\), so \(A^3 = -A\) and \(A^4 = I\). Test each option.
Updated On: Nov 11, 2026
  • \(A^3 + I = A(A^3 - I)\)
  • \(A^4 - I = A^2 + I\)
  • \(A^2 + I = A(A^2 - I)\)
  • \(A^3 - I = A(A - I)\)
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The Correct Option is C

Solution and Explanation

\(A^2 = \begin{bmatrix} 0\;\;-1\\1\;\;0 \end{bmatrix}\begin{bmatrix} 0\;\;-1\\1\;\;0 \end{bmatrix} = \begin{bmatrix} -1\;\;0\\0\;\;-1 \end{bmatrix} = -I\), so \(A^3 = -A\) and \(A^4 = I\).
(1) LHS \(= -A + I\); RHS \(= A(-A - I) = -A^2 - A = I - A\). Equal, so correct.
(2) LHS \(= I - I = 0\); RHS \(= -I + I = 0\). Equal, so correct.
(3) LHS \(= -I + I = 0\); RHS \(= A(-I - I) = -2A \neq 0\). Not equal, so this statement is not correct.
(4) LHS \(= -A - I\); RHS \(= A^2 - A = -I - A\). Equal, so correct.
Answer: (3) \(A^2 + I = A(A^2 - I)\)
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