If A and B are the points of intersection of the circles \( x^2 + y^2 - 4x + 6y - 3 = 0 \) and \( x^2 + y^2 + 2x - 2y - 2 = 0 \), then the distance between A and B is:
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To find the distance between the intersection points of two circles, use the geometry of the system of equations and apply the distance formula.
Step 1: Equations of the circles.
The equations of the two circles are:
\[
x^2 + y^2 - 4x + 6y - 3 = 0
\]
and
\[
x^2 + y^2 + 2x - 2y - 2 = 0
\]
Step 2: Subtract the two equations.
Subtract the second equation from the first:
\[
(x^2 + y^2 - 4x + 6y - 3) - (x^2 + y^2 + 2x - 2y - 2) = 0
\]
Simplifying:
\[
-6x + 8y - 1 = 0 \quad \Rightarrow \quad 3x - 4y = \frac{1}{2}
\]
Step 3: Find the distance between the points.
Using the distance formula between the points of intersection of two circles, we find the distance between A and B to be:
\[
\text{Distance} = \frac{\sqrt{231}}{5}
\]