Question:
If \(9^{2x – 1} – 81^{x-1} = 1944\), then x is
If \(9^{2x – 1} – 81^{x-1} = 1944\), then x is
Updated On: Jul 21, 2025
- 3
- \(\frac{9}{4}\)
- \(\frac{4}{9}\)
- \(\frac{1}{3}\)
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The Correct Option is B
Solution and Explanation
\(9^{(2x−1)}−81^{(x−1)}=1944\)
\(9^{(2x−1)}−9^{(2x−2)}=1944\)
\(9^{2x−2}×8=1944,\)
\(3^{(4x−4)}=3^5\)
\(4x−4=5\)
\(x=\frac{9}{4}\)
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