Question:

If 80 g of copper sulphate \(\mathrm{CuSO_4 \cdot 5H_2O}\) is dissolved in deionised water to make 5L of solution. The concentration of the copper sulphate solution is x \(\times\) 10\(^{-3}\) mol L\(^{-1}\). The value of x is _____________.

[Atomic masses Cu : 63.54u, S : 32u, O : 16u, H : 1u]

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Find the molar mass of the pentahydrate, then moles per litre.
Updated On: Nov 4, 2026
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Correct Answer: 64

Solution and Explanation

Molar mass of \(\mathrm{CuSO_4\cdot5H_2O}\) = 63.54 + 32 + 4(16) + 5(18) = 249.54 g/mol.
Moles = 80/249.54 = 0.3206 mol.
Molarity = 0.3206/5 L = 0.06412 mol/L = 64.1 x 10\(^{-3}\) mol/L.
x = 64 (nearest integer).
Answer: 64
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