If \(\frac{3x+2}{(x+1)(2x^2+3)} = \frac{A}{x+1}+ \frac{Bx+C}{2x^2+3}\), then A - B + C=
2
1
3
6
To solve the given equation and find \( A - B + C \), let's perform partial fraction decomposition. The given equation is:
\(\frac{3x + 2}{(x+1)(2x^2+3)} = \frac{A}{x+1} + \frac{Bx+C}{2x^2+3}\)
To decompose the fraction, multiply both sides by \((x+1)(2x^2+3)\) to get rid of the denominators:
\(3x + 2 = A(2x^2 + 3) + (Bx + C)(x + 1)\)
Expand the right side of the equation:
Combine the terms:
\(3x + 2 = 2Ax^2 + 3A + Bx^2 + (B + C)x + C\)
Coefficient matching for the powers of \( x \):
Now, solve this system of equations:
From equation 1:
\(B = -2A\)
Substitute \(B = -2A\) in equation 2:
\( -2A + C = 3\)
\(C = 3 + 2A\)
Substitute \(C = 3 + 2A\) in equation 3:
\(3A + (3 + 2A) = 2\)
\(5A + 3 = 2\)
\(5A = 2 - 3\)
\(5A = -1\)
\(A = -\frac{1}{5}\)
Find values of \(B\) and \(C\):
\(B = -2A = 2 \times \frac{1}{5} = \frac{2}{5}\)
\(C = 3 + 2A = 3 + 2 \times -\frac{1}{5} = 3 - \frac{2}{5} = \frac{15}{5} - \frac{2}{5} = \frac{13}{5}\)
Calculate \(A - B + C\):
\(-\frac{1}{5} - \frac{2}{5} + \frac{13}{5} = \frac{-1 - 2 + 13}{5} = \frac{10}{5} = 2\)
Therefore, the value of \(A - B + C\) is 2.
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If (-c, c) is the set of all values of x for which the expansion is (7 - 5x)-2/3 is valid, then 5c + 7 =
If a line ax + 2y = k forms a triangle of area 3 sq.units with the coordinate axis and is perpendicular to the line 2x - 3y + 7 = 0, then the product of all the possible values of k is
The quadratic equation whose roots are
\(l = \lim_{\theta\to0} \frac{3sin\theta - 4sin^3\theta}{\theta}\)
m = \(\lim_{\theta\to0} \frac{2tan\theta}{\theta(1-tan^2\theta)}\) is
Consider z1 and z2 are two complex numbers.
For example, z1 = 3+4i and z2 = 4+3i
Here a=3, b=4, c=4, d=3
∴z1+ z2 = (a+c)+(b+d)i
⇒z1 + z2 = (3+4)+(4+3)i
⇒z1 + z2 = 7+7i
Properties of addition of complex numbers
It is similar to the addition of complex numbers, such that, z1 - z2 = z1 + ( -z2)
For example: (5+3i) - (2+1i) = (5-2) + (-2-1i) = 3 - 3i
Considering the same value of z1 and z2 , the product of the complex numbers are
z1 * z2 = (ac-bd) + (ad+bc) i
For example: (5+6i) (2+3i) = (5×2) + (6×3)i = 10+18i
Properties of Multiplication of complex numbers
Note: The properties of multiplication of complex numbers are similar to the properties we discussed in addition to complex numbers.
Associative law: Considering three complex numbers, (z1 z2) z3 = z1 (z2 z3)
Read More: Complex Numbers and Quadratic Equations
If z1 / z2 of a complex number is asked, simplify it as z1 (1/z2 )
For example: z1 = 4+2i and z2 = 2 - i
z1 / z2 =(4+2i)×1/(2 - i) = (4+i2)(2/(2²+(-1)² ) + i (-1)/(2²+(-1)² ))
=(4+i2) ((2+i)/5) = 1/5 [8+4i + 2(-1)+1] = 1/5 [8-2+1+41] = 1/5 [7+4i]