If 250 cm3 of an aqueous solution containing 0.73 g of a protein A is isotonic with one litre of another aqueous solution containing 1.65 g of a protein B, at 298 K, the ratio of the molecular masses of A and B is ______ \(\times 10^{-2}\) (to the nearest integer).
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Correct Answer: 177
Solution and Explanation
\(C_A = \dfrac{0.73/M_A}{0.250\ \mathrm{L}}\), \(C_B = \dfrac{1.65/M_B}{1\ \mathrm{L}}\).
Equating: \(\dfrac{0.73}{0.25\,M_A} = \dfrac{1.65}{M_B}\), so \(\dfrac{M_A}{M_B} = \dfrac{0.73}{0.25\times1.65} = \dfrac{0.73}{0.4125} = 1.7697\).
\(1.7697 = 176.97\times10^{-2} \approx 177\times10^{-2}\).
Answer: 177
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