To find the value of \(x^x\) given the equation \(2^x + 2^{x+1} = 48\), we start by simplifying the equation.
The term \(2^{x+1}\) can be rewritten using the property of exponents as \(2 \times 2^x\). Therefore, the equation becomes:
\(2^x + 2 \times 2^x = 48\)
Combining like terms, we factor out \(2^x\):
\(2^x (1 + 2) = 48\)
This simplifies to:
\(2^x \times 3 = 48\)
Solving for \(2^x\), we divide both sides by 3:
\(2^x = \frac{48}{3} = 16\)
We know \(16\) is \(2^4\), so:
\(2^x = 2^4\)
By comparing the exponents, we find:
\(x = 4\)
Now, we calculate \(x^x\) using this value of \(x\):
\(x^x = 4^4\)
Calculating \(4^4\):
\(4^4 = 4 \times 4 \times 4 \times 4 = 256\)
Therefore, the value of \(x^x\) is 256.
Thus, the correct option is 256.