Question:

If \(12\) men or \(20\) women can do a work in \(54\) days, then in how many days can \(9\) men and \(12\) women together do the work?

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Remember:
  • Work and time are inversely proportional to efficiency
  • If: \[ a \text{ men} = b \text{ women} \] then efficiencies can be converted easily
  • More workers $\Rightarrow$ fewer days
Updated On: May 25, 2026
  • \(38\) days
  • \(32\) days
  • \(40\) days
  • \(35\) days
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The Correct Option is C

Solution and Explanation

Concept: Work done is calculated using: \[ \text{Work} = \text{Efficiency} \times \text{Time} \] If two groups complete the same work in the same time, then their total efficiencies are equal.

Step 1:
Find the relation between efficiency of men and women. Given: \[ 12 \text{ men complete work in } 54 \text{ days} \] Also: \[ 20 \text{ women complete same work in } 54 \text{ days} \] Hence: \[ 12 \text{ men} = 20 \text{ women} \] Dividing by \(4\): \[ 3 \text{ men} = 5 \text{ women} \] Therefore: \[ 1 \text{ man} = \frac{5}{3} \text{ women} \]

Step 2:
Convert all workers into women-equivalent. Given: \[ 9 \text{ men and } 12 \text{ women} \] Since: \[ 1 \text{ man} = \frac{5}{3} \text{ women} \] \[ 9 \text{ men} = 9 \times \frac{5}{3} = 15 \text{ women} \] Total equivalent women: \[ 15 + 12 = 27 \text{ women} \]

Step 3:
Calculate the required number of days. We know: \[ 20 \text{ women complete work in } 54 \text{ days} \] Using inverse proportion: \[ \text{Days} = \frac{20 \times 54}{27} \] \[ = 40 \] Therefore, \[ \boxed{40\text{ days}} \]
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