Concept:
For recurring decimals:
\[
0.\overline{ab}=\frac{ab}{99}
\]
Step 1: Separate integer and decimal parts.
Given:
\[
10.\overline{36}=10+0.\overline{36}
\]
Now:
\[
0.\overline{36}=\frac{36}{99}
\]
Simplify:
\[
=\frac{4}{11}
\]
So:
\[
10.\overline{36}=10+\frac{4}{11}
\]
Step 2: Convert into improper fraction.
\[
=\frac{110+4}{11}
\]
\[
=\frac{114}{11}
\]
Thus:
\[
p=114,\quad q=11
\]
and:
\[
\gcd(114,11)=1
\]
Step 3: Find \(p+q\).
\[
114+11=125
\]
Thus, the required answer is:
\[
\boxed{125}
\]