If $1+\sin^2(2A)=3\sin A\cos A$, then what are the possible values of $\tan A$?
$1/8,\,4$
We are given \[ 1+\sin^2A=3\sin A\cos A. \] Divide both sides by $\cos^2 A$ (valid for $\cos A\neq0$): \[ \frac{1}{\cos^2A}+\tan^2A=3\tan A. \] But $\frac{1}{\cos^2A}=1+\tan^2A$. So \[ 1+\tan^2A+\tan^2A=3\tan A \quad\Rightarrow\quad 1+2\tan^2A=3\tan A. \] Hence quadratic: \[ 2\tan^2A-3\tan A+1=0. \] Solve: \[ \tan A=\frac{3\pm \sqrt{9-8}}{4}=\frac{3\pm1}{4}. \] So $\tan A=\tfrac12$ or $1$. \[ \boxed{\tfrac12,\,1} \]
In a special racing event, the person who enclosed the maximum area would be the winner and would get ₹ 100 every square metre of area covered by him/her. Jonsson, who successfully completed the race and was the eventual winner, enclosed the area shown in the figure below. What is the prize money won?
\(\textit{Note: The arc from C to D makes a complete semi-circle. Given: }\) $AB=3$ m, $BC=10$ m, $CD=BE=2$ m.

A lawn is in the form of an isosceles triangle. The cost of turfing on it came to $₹ 1{,}200$ at ₹ 4 per m$^2$. If the base be 40 m long, find the length of each side.
If \[ 2\sin\alpha + 15\cos^{2}\alpha = 7, \quad 0^\circ < \alpha < 90^\circ, \] find \(\cot\alpha\).
