Question

Identify the product formed when Ethyl alcohol is heated with concentrated \( H_2SO_4 \) at \(443\,K\).

• A. Ethane
• B. Ethene
• C. Diethyl ether
• D. Acetaldehyde

Hint:

At \(413\,K\), ethanol forms diethyl ether, while at \(443\,K\) it forms ethene due to dehydration.

Answer 1

The Correct Option is B

Concept: Concentrated \(H_2SO_4\) acts as a dehydrating agent. At high temperature \(443\,K\), ethanol undergoes elimination (dehydration) to form ethene.

Step 1: Write the dehydration reaction. \[ C_2H_5OH \xrightarrow[\;443K\;]{conc.\ H_2SO_4} C_2H_4 + H_2O \]

Step 2: Identify the product. The product formed is \[ \text{Ethene } (C_2H_4) \]