Question:
Identify the pair in which the difference in bond order value is maximum.
Identify the pair in which the difference in bond order value is maximum.
Show Hint
Bond order decreases with the addition of electrons to antibonding orbitals.
- Higher bond order implies stronger and shorter bonds.
- Higher bond order implies stronger and shorter bonds.
Updated On: Mar 6, 2026
- \( O_2^-, O_2^+ \)
- \( O_2^{2-}, O_2^{2+} \)
- \( O_2, O_2^{2+} \)
- \( O_2^+, O_2^{2+} \)
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The Correct Option is B
Solution and Explanation
The bond order of an oxygen molecule and its ions can be calculated using: \[ \text{Bond Order} = \frac{(N_b - N_a)}{2} \] where \( N_b \) is the number of bonding electrons and \( N_a \) is the number of antibonding electrons. 1. Bond Order Calculations: - \( O_2 \) (neutral) = 2.0 - \( O_2^+ \) = 2.5 - \( O_2^- \) = 1.5 - \( O_2^{2+} \) = 3.0 - \( O_2^{2-} \) = 1.0 2. Difference in Bond Order: - \( O_2^{2-} \) vs \( O_2^{2+} \) \[ \Delta B.O = 3.0 - 1.0 = 2.0 \] - This is the maximum difference among the given pairs. Thus, the correct answer is \(\boxed{O_2^{2-}, O_2^{2+}}\).
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