Identify the median class for the following grouped data:
\[\begin{array}{|c|c|} \hline \textbf{Class interval} & \textbf{Frequency} \\ \hline 5-10 & 5 \\ 10-15 & 15 \\ 15-20 & 22 \\ 20-25 & 25 \\ 25-30 & 10 \\ 30-35 & 3 \\ \hline \end{array}\]
Step 1: Calculate the total frequency (N). \[ N = 5 + 15 + 22 + 25 + 10 + 3 = 80 \]
Step 2: Find the position of the median. The median is the value at the \( N/2 \)-th position. \[ \text{Median Position} = \frac{80}{2} = 40 \]
Step 3: Calculate the cumulative frequency (CF) for each class.
\[\begin{array}{|c|c|c|} \hline \text{Class interval} & \text{Frequency (f)} & \text{Cumulative Frequency (CF)} \\ \hline 5-10 & 5 & 5 \\ 10-15 & 15 & 20 \\ 15-20 & 22 & 42 \\ 20-25 & 25 & 67 \\ 25-30 & 10 & 77 \\ 30-35 & 3 & 80 \\ \hline \end{array}\]
Step 4: Identify the median class. The median class is the class whose cumulative frequency is the first to be greater than or equal to the median position (40). The cumulative frequency 42 is the first one greater than 40. The corresponding class interval is 15-20.
If \(f(t)\) is the inverse Laplace transform of \( F(s) = \frac{s+1+s^{-2}}{s^2-1} \), then \(f(t)\) is
Match LIST-I with LIST-II
LIST-I (Differential Equation)
(A) \(\frac{dy}{dx} = 2x(y-x^2+1)\)
(B) \(x\frac{dy}{dx} + 2(x^2+1)y=6\)
(C) \((x^2+1)\frac{dy}{dx} + 2xy = x \sin x\)
(D) \(x^3\frac{dy}{dx} + 2xy = 2x^2e^{x^2}\)
LIST-II (Integrating Factor)
(I) \(x^2\)
(II) \(e^{-x^2}\)
(III) \(x^2e^x\)
(IV) \(1+x^2\)
Choose the correct answer from the options given below:
The coefficient of correlation of the above two data series will be equal to \(\underline{\hspace{1cm}}\)
\[\begin{array}{|c|c|} \hline X & Y \\ \hline -3 & 9 \\ -2 & 4 \\ -1 & 1 \\ 0 & 0 \\ 1 & 1 \\ 2 & 4 \\ 3 & 9 \\ \hline \end{array}\]