Question

Hydrolysis of \(CH_3CH_2NO_2\) with \(85\%\ H_2SO_4\) gives which of the following compound

• A. \(CH_3CH_2OH\)
• B. \(C_2H_6\)
• C. \(CH_3CHNO\)
• D. \(CH_3COOH\)

Hint:

Primary nitroalkanes on strong acidic hydrolysis form carboxylic acids. \[ RCH_2NO_2 \rightarrow RCOOH \]

Answer 1

The Correct Option is D

Concept:
Nitroalkanes can undergo hydrolysis under strong acidic conditions. Primary nitroalkanes on hydrolysis with strong acid give carboxylic acids. The given compound is: \[ CH_3CH_2NO_2 \] This is nitroethane, a primary nitro compound.

Step 1: Identify the compound.
The compound: \[ CH_3CH_2NO_2 \] is nitroethane. It contains the nitro group: \[ -NO_2 \] attached to an ethyl group.

Step 2: Recall the reaction of primary nitroalkanes.
Primary nitroalkanes on hydrolysis with strong acid give carboxylic acids. The general conversion is: \[ RCH_2NO_2 \xrightarrow{85\%\ H_2SO_4} RCOOH \]

Step 3: Apply the reaction to nitroethane.
Here: \[ CH_3CH_2NO_2 \] On hydrolysis, it gives: \[ CH_3COOH \] This compound is acetic acid.

Step 4: Check the options.
Option (A) \(CH_3CH_2OH\) is ethanol, not the product.
Option (B) \(C_2H_6\) is ethane, not formed in this reaction.
Option (C) \(CH_3CHNO\) is not the expected hydrolysis product.
Option (D) \(CH_3COOH\) is acetic acid and is correct. Hence, the correct answer is: \[ \boxed{(D)\ CH_3COOH} \]