Question:
Hybridisation of carbon in ethyne (acetylene) is:
Hybridisation of carbon in ethyne (acetylene) is:
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Triple bond = $sp$; Double bond = $sp^{2}$; Single bond = $sp^{3}$.
Updated On: May 5, 2026
- sp$^{3}$
- sp$^{2}$
- sp
- sp$^{3}$d
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The Correct Option is C
Solution and Explanation
Step 1: Concept
Hybridization is determined by the number of sigma ($\sigma$) bonds and lone pairs around an atom.
Step 2: Meaning
In ethyne ($HC \equiv CH$), each carbon atom is triple-bonded to another carbon and single-bonded to a hydrogen.
Step 3: Analysis
Each carbon in ethyne forms 2 $\sigma$ bonds (one with $H$ and one with $C$) and 2 $\pi$ bonds. A steric number of 2 corresponds to $sp$ hybridization.
Step 4: Conclusion
This results in a linear molecular geometry with a bond angle of 180$^{\circ}$. Final Answer: (C)
Hybridization is determined by the number of sigma ($\sigma$) bonds and lone pairs around an atom.
Step 2: Meaning
In ethyne ($HC \equiv CH$), each carbon atom is triple-bonded to another carbon and single-bonded to a hydrogen.
Step 3: Analysis
Each carbon in ethyne forms 2 $\sigma$ bonds (one with $H$ and one with $C$) and 2 $\pi$ bonds. A steric number of 2 corresponds to $sp$ hybridization.
Step 4: Conclusion
This results in a linear molecular geometry with a bond angle of 180$^{\circ}$. Final Answer: (C)
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