Step 1: Understanding the Concept
Complete combustion of a hydrocarbon involves reacting it with oxygen (\(O_2\)) to produce carbon dioxide (\(CO_2\)) and water (\(H_2O\)). To find the molar ratio, we must write a balanced chemical equation. Step 2: Key Formula or Approach
The general formula for the combustion of a hydrocarbon \(C_xH_y\) is:
\[ C_xH_y + \left(x + \frac{y}{4}\right)O_2 \to xCO_2 + \frac{y}{2}H_2O \] Step 3: Detailed Explanation
1. For Propane, \(x = 3\) and \(y = 8\).
2. Carbon balancing: 3 atoms of C produce \(3CO_2\).
3. Hydrogen balancing: 8 atoms of H produce \(4H_2O\).
4. Oxygen balancing: - From \(CO_2\): \(3 \times 2 = 6\) oxygen atoms.
- From \(H_2O\): \(4 \times 1 = 4\) oxygen atoms.
- Total Oxygen atoms needed = \(6 + 4 = 10\).
- Since oxygen exists as \(O_2\), the number of moles of \(O_2\) is \(10 / 2 = 5\).
5. Balanced Equation: \[ C_3H_8 + 5O_2 \to 3CO_2 + 4H_2O \] Step 4: Final Answer
5 moles of oxygen are required to combust 1 mole of propane.