Question

How many dibromo products are possible for ‘B’ (including stereoisomer)?

• A. 3
• B. 5
• C. 6
• D. 8

Answer 1

The Correct Option is D

Step 1: Understanding the Reaction.
The reaction involves the addition of bromine (Br₂) in the presence of light (hv), which suggests a free radical substitution mechanism. The presence of light initiates the formation of free radicals, which results in the bromination of the compound. In the first step, A is formed by the free radical bromination of the alkene.
Step 2: Analyzing the Stereoisomerism.
Since the bromination occurs under light, the reaction mechanism will lead to the formation of both enantiomers (optical isomers) as well as diastereoisomers. In the case of alkene bromination, two stereoisomers (enantiomers) will form at each of the possible carbon positions where the bromine atoms are added.
Step 3: Counting the Products.
When considering stereoisomerism, if there are two distinct positions where the bromine atoms can be added (like in a non-symmetrical alkene), the number of possible stereoisomers increases. Typically, for each unique position, you could have up to four possible products (two enantiomers and two diastereoisomers).
Step 4: Conclusion.
The number of possible dibromo products, considering stereoisomers, will be 8.

Final Answer: 8