To understand how an electrochemical cell can be converted into an electrolytic cell, let's first review the basic operation of each type of cell:
To convert an electrochemical cell into an electrolytic cell, one needs to apply an external force that counteracts the natural direction of the reactions taking place in the electrochemical cell. This is done by:
Therefore, the correct way to convert an electrochemical cell into an electrolytic cell is by applying an external opposite potential greater than \(E^\circ_{\text{cell}}\). This approach forces the redox reaction to proceed in the non-spontaneous direction, effectively using the cell as an electrolytic cell.
Let's evaluate the other options:
In conclusion, the correct answer is: Applying an external opposite potential greater than \(E^\circ_{\text{cell}}\).
To convert an electrochemical cell into an electrolytic cell, an external potential needs to be applied in the opposite direction. This applied potential should be greater than the standard cell potential \( E^\circ_{\text{cell}} \). When this condition is met, the cell reaction reverses, and the electrochemical cell functions as an electrolytic cell.
Two p-n junction diodes \(D_1\) and \(D_2\) are connected as shown in the figure. \(A\) and \(B\) are input signals and \(C\) is the output. The given circuit will function as a _______. 
A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol$^{-1}$) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is $____________ \(\times 10^{-2}\). (nearest integer)
[Given : $K_{b}$ of the solvent = 5.0 K kg mol$^{-1}$]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.