Step 1: Define radioactive half-life (\(t_{1/2}\)).
The half-life is the time required for a quantity of a radioactive substance to be reduced to half of its initial value.
Step 2: State the formula relating half-life and the decay constant.
Radioactive decay is a first-order process. The relationship between the half-life and the decay constant (\(\lambda\)) is:
\[ t_{1/2} = \frac{\ln(2)}{\lambda} \]
Step 3: Analyze the relationship.
From the formula, we can see two things:
1. The half-life (\(t_{1/2}\)) is inversely proportional to the decay constant (\(\lambda\)).
2. The formula does not contain any terms for the initial or final concentration/amount of the substance. This means the half-life is independent of these quantities.
Conclusion: The half-life is independent of the initial concentration and inversely proportional to the decay constant.
If \(f(t)\) is the inverse Laplace transform of \( F(s) = \frac{s+1+s^{-2}}{s^2-1} \), then \(f(t)\) is
Match LIST-I with LIST-II
LIST-I (Differential Equation)
(A) \(\frac{dy}{dx} = 2x(y-x^2+1)\)
(B) \(x\frac{dy}{dx} + 2(x^2+1)y=6\)
(C) \((x^2+1)\frac{dy}{dx} + 2xy = x \sin x\)
(D) \(x^3\frac{dy}{dx} + 2xy = 2x^2e^{x^2}\)
LIST-II (Integrating Factor)
(I) \(x^2\)
(II) \(e^{-x^2}\)
(III) \(x^2e^x\)
(IV) \(1+x^2\)
Choose the correct answer from the options given below: