




Step 1: Analyze the electric field inside and outside the sphere.
- Inside the sphere \((r < R)\): Electric field increases linearly with r due to the uniformly distributed charge.
- Outside the sphere \((r ≥ R)\): Electric field decreases as \(\frac{1}{ r^2}\) , behaving like a point charge at the center.
Step 2: Draw the graph.
- Combine the two observations to get the correct graph for the electric field variation.
Final Answer: The correct graph is represented by option (4).
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,


A metallic ring is uniformly charged as shown in the figure. AC and BD are two mutually perpendicular diameters. Electric field due to arc AB to O is ‘E’ magnitude. What would be the magnitude of electric field at ‘O’ due to arc ABC? 
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)