To determine the correctness of the given statements, let's analyze each one regarding kinetic theory and properties of gases:
After analyzing both statements with theoretical backing:
Thus, the correct answer is: Both Statement I and Statement II are true.
The mean free path (\(\lambda\)) of gas molecules is given by:
\[\lambda = \frac{RT}{\sqrt{2} \pi d^2 N_A P}.\]
Here, \(\lambda \propto \frac{1}{d^2}\), verifying Statement (I).
The average kinetic energy of gas molecules is:
\[KE = \frac{f}{2} nRT,\]
where \(KE \propto T\), confirming Statement (II).
Thus, both Statement I and Statement II are correct.
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,

What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)