Question:
Given below are two statements:
Statement I: The dipole moment of R–CN is greater than R–NC and R–NC can undergo hydrolysis under acidic medium to produce R–COOH.
Statement II: R–CN hydrolyses under acidic medium to produce a compound which on treatment with SOCl$_2$, followed by the addition of NH$_3$ gives another compound (X). This compound (X) on treatment with NaOCl/NaOH gives a product, that on treatment with CHCl$_3$/KOH/$\Delta$ produces R–NC.
In the light of the above statements, choose the correct answer from the options given below.
Given below are two statements:
Statement I: The dipole moment of R–CN is greater than R–NC and R–NC can undergo hydrolysis under acidic medium to produce R–COOH.
Statement II: R–CN hydrolyses under acidic medium to produce a compound which on treatment with SOCl$_2$, followed by the addition of NH$_3$ gives another compound (X). This compound (X) on treatment with NaOCl/NaOH gives a product, that on treatment with CHCl$_3$/KOH/$\Delta$ produces R–NC.
In the light of the above statements, choose the correct answer from the options given below.
Statement I: The dipole moment of R–CN is greater than R–NC and R–NC can undergo hydrolysis under acidic medium to produce R–COOH.
Statement II: R–CN hydrolyses under acidic medium to produce a compound which on treatment with SOCl$_2$, followed by the addition of NH$_3$ gives another compound (X). This compound (X) on treatment with NaOCl/NaOH gives a product, that on treatment with CHCl$_3$/KOH/$\Delta$ produces R–NC.
In the light of the above statements, choose the correct answer from the options given below.
Show Hint
Nitriles hydrolyse to carboxylic acids, while isocyanides are formed from primary amines via the carbylamine reaction.
Updated On: Apr 3, 2026
- Both Statement I and Statement II are true
- Both Statement I and Statement II are false
- Statement I is true but Statement II is false
- Statement I is false but Statement II is true
Show Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Step 1: Evaluation of Statement I.
Although the dipole moment of R–CN is greater than that of R–NC, the statement incorrectly mentions that R–NC undergoes acidic hydrolysis to form R–COOH. In reality, nitriles (R–CN) undergo acidic hydrolysis to give carboxylic acids, whereas isocyanides (R–NC) do not. Hence, Statement I is false.
Step 2: Evaluation of Statement II.
R–CN undergoes acidic hydrolysis to form R–COOH. Treatment with SOCl$_2$ converts it into R–COCl, which on reaction with NH$_3$ forms R–CONH$_2$ (amide). The amide undergoes Hofmann degradation with NaOCl/NaOH to form R–NH$_2$, which on treatment with CHCl$_3$/KOH/$\Delta$ gives R–NC via the carbylamine reaction. Thus, Statement II is true.
Step 3: Conclusion.
Statement I is false and Statement II is true.
Although the dipole moment of R–CN is greater than that of R–NC, the statement incorrectly mentions that R–NC undergoes acidic hydrolysis to form R–COOH. In reality, nitriles (R–CN) undergo acidic hydrolysis to give carboxylic acids, whereas isocyanides (R–NC) do not. Hence, Statement I is false.
Step 2: Evaluation of Statement II.
R–CN undergoes acidic hydrolysis to form R–COOH. Treatment with SOCl$_2$ converts it into R–COCl, which on reaction with NH$_3$ forms R–CONH$_2$ (amide). The amide undergoes Hofmann degradation with NaOCl/NaOH to form R–NH$_2$, which on treatment with CHCl$_3$/KOH/$\Delta$ gives R–NC via the carbylamine reaction. Thus, Statement II is true.
Step 3: Conclusion.
Statement I is false and Statement II is true.
Was this answer helpful?
0
1
Top JEE Main Chemistry Questions
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)- At equilibrium the concentrations of and in a sealed vessel at . What will be for the reaction
- Find out the major products from the following reactions
Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
- The correct order of atomic radii is:
View More Questions
Top JEE Main reaction mechanism Questions
- Which reagent gives bright red ppt. With \(Ni^{2+}\) in basic medium?
- Match the following:
LIST I LIST II A Lyman I Near IR B Balmer II Far IR C Paschen III Visible D p-fund IV UV - Best reducing agent among the given ions are:
The correct order of the rate of reaction of the following reactants with nucleophile by \( \mathrm{S_N1} \) mechanism is:
(Given: Structures I and II are rigid)
- Given below are two statements:
Statement I: Phenol on treatment with \( \mathrm{CHCl_3/aq.\ KOH} \) under refluxing condition, followed by acidification produces p-hydroxy benzaldehyde as the major product and o-hydroxy benzaldehyde as the minor product.
Statement II: The mixture of p-hydroxybenzaldehyde and o-hydroxybenzaldehyde can be easily separated through steam distillation.
In the light of the above statements, choose the correct answer from the options given below
View More Questions
Top JEE Main Questions
- In a hydrogen like atom, when an electron jumps from the $M$ - shell to the $L$ - shell, the wavelength of emitted radiation is $\lambda$. If an electron jumps from $N$-shell to the $L$-shell, the wavelength of emitted radiation will be :
- Two masses $m$ and $\frac{m}{2}$ are connected at the two ends of a massless rigid rod of length $l$. The rod is suspended by a thin wire of torsional constant $k$ at the centre of mass of the rod-mass system(see figure). Because of torsional constant $k$, the restoring torque is $\tau =k\theta$ for angular displacement $\theta$. If the rod is rota ted by $\theta_0$ and released, the tension in it when it passes through its mean position will be:
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)- The value of is
- The number of terms of an is even. The sum of the odd terms is and of the even terms is . The last term exceeds the first by . Then the number of terms in the series is ______.
View More Questions