Given below are two statements:
Statement I: Chromosomes are fully condensed at the end of prophase I.
Statement II: Meiosis I resembles mitosis.
Choose the most appropriate answer from the options given below:
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Remember:
Meiosis I = Reduction division (different from mitosis)
Meiosis II = Equational division (resembles mitosis)
A common exam trick is confusing Meiosis I and Meiosis II.
Statement I is incorrect, but Statement II is true
Both Statement I and Statement II are true
Both Statement I and Statement II are false
Statement I is correct, but Statement II is false
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The Correct Option isD
Solution and Explanation
Concept:
Meiosis is a special type of cell division producing haploid cells from diploid parent cells. It occurs in two stages:
Meiosis I and Meiosis II
Meiosis I is called reduction division because chromosome number becomes half.
Mitosis produces identical daughter cells without reduction in chromosome number.
Step 1: Analyze Statement I.
Prophase I is the first stage of meiosis I.
It consists of five sub-stages:
• Leptotene
• Zygotene
• Pachytene
• Diplotene
• Diakinesis
During the final stage called diakinesis, chromosomes become maximally shortened and fully condensed.
Thus chromosomes are fully condensed at end of prophase I.
So Statement I is correct.
Step 2: Analyze Statement II.
Meiosis I involves:
• Synapsis of homologous chromosomes
• Crossing over
• Separation of homologous chromosomes
• Reduction in chromosome number
These processes do not occur in mitosis.
Therefore meiosis I is fundamentally different from mitosis.
Step 3: Understand which stage resembles mitosis.
Meiosis II resembles mitosis because in both divisions:
• Sister chromatids separate
• Chromosome number remains unchanged during division
• Similar spindle behavior occurs
Hence saying “Meiosis I resembles mitosis” is incorrect.
Step 4: Evaluate statements.
Statement I → True
Statement II → False
Thus correct conclusion becomes
\[
\boxed{\text{Statement I is correct but Statement II is false}}
\]
\[
\boxed{\text{Correct Answer = Option (4)}}
\]