Step 1: Analyze Statement I. The velocity \( \vec{v} \) is given by: \[ \vec{v} = \frac{d\vec{s}}{dt}. \] Integrating both sides with respect to time: \[ \int d\vec{s} = \int \vec{v} \, dt. \] The area under the velocity-time (\( \vec{v} \)-\( t \)) graph gives displacement. Hence, Statement I is true.
Step 2: Analyze Statement II. The acceleration \( \vec{a} \) is given by: \[ \vec{a} = \frac{d\vec{v}}{dt}. \] Integrating both sides with respect to time: \[ \int d\vec{v} = \int \vec{a} \, dt. \] The area under the acceleration-time (\( \vec{a} \)-\( t \)) graph gives the change in velocity. Hence, Statement II is also true.
Final Answer: Both statements are: \[ \boxed{\text{True.}} \]
A wire of 60 cm length and mass 10 g is suspended by a pair of flexible leads in a magnetic field of 0.60 T as shown in the figure. The magnitude of the current required to remove the tension in the supporting leads is:

A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol$^{-1}$) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is $____________ \(\times 10^{-2}\). (nearest integer)
[Given : $K_{b}$ of the solvent = 5.0 K kg mol$^{-1}$]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.