Solution:
For a truck and a car moving with the same kinetic energy, the distance to stop under the same retarding force can be determined by using the equation:
\[
\text{Work done} = \Delta KE
\]
Since the initial kinetic energy is the same for both vehicles, the work done (force times distance) to bring them to rest will be equal. Thus, both vehicles come to rest in the same distance.
Statement II:
In Statement II, when a car changes its direction from east to north, its speed may remain constant, but its velocity is changing because velocity is a vector quantity. Since the direction of velocity is changing, the car has acceleration. Therefore, the acceleration is not zero.
\[
\Delta \vec{V} = \vec{V_f} - \vec{V_i}
\]
As velocity is changing, acceleration \( \vec{a} \neq 0 \).
Thus, Statement II is incorrect.
Thus, the correct answer is \( \boxed{1} \).
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,

What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)