Step 1: Understanding the fringe width formula. The fringe width in Young’s double-slit experiment is given by: \[ \beta = \frac{\lambda D}{d}, \] where: - \( \lambda \) is the wavelength of the light, - \( D \) is the distance between slits and screen, - \( d \) is the separation between the slits.
Step 2: Analyzing Assertion (A). Since \( \beta \propto \lambda \), red light (\(\lambda\) is larger) produces wider fringes than blue light (\(\lambda\) is smaller). Thus, Assertion (A) is incorrect because it states the opposite.
Step 3: Analyzing Reason (R). The fringe width is indeed proportional to the wavelength, which is a correct statement.
Since (A) is false but (R) is true, the correct choice is: \[ \boxed{\text{(2) (A) is false, but (R) is true.}} \]
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,


What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)