Question:

Ga (atomic mass 70 u) crystallizes in a hexagonal close packed structure. The total number of voids in 0.581 g of Ga is __________ \(\times\) \(10^{21}\). (Round off to the Nearest Integer). [Given : \(\mathrm{N_A}\) = 6.023 \(\times\) \(10^{23}\)]

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In hcp (or ccp) there are 3 voids per atom (1 octahedral + 2 tetrahedral). Count the atoms in 0.581 g and multiply by 3.
Updated On: Nov 4, 2026
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Correct Answer: 15

Solution and Explanation

Number of Ga atoms = \(\frac{0.581}{70}\times 6.023\times 10^{23}\approx 5.0\times 10^{21}\).
In a hexagonal close packed structure, for N atoms there are N octahedral voids and 2N tetrahedral voids, i.e. 3N voids in total.
Total voids = \(3\times 5.0\times 10^{21}=15\times 10^{21}\).
Answer: 15
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