Step 1: Stack size. Total=11+9+13+7=40, so 40/4=10 chips per stack.
Step 2: Rule. Each of 4 stacks needs at least 1 white chip. Only 9 white chips exist.
Step 3: Bound. Other 3 stacks need at least 3 white chips total. Max in one stack <= 9-3=6.
Step 4: Achievable. A valid distribution exists giving stack 1: 6 white, 2 orange, 1 black, 1 yellow (total 10); other stacks share the rest evenly, all totals work out to 10 each with all colours present.
Final Answer: The maximum number of white chips possible in one stack is 6.