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for x in minus1 1 evaluate sin 2 sin inverse x
Question:
For \(x\in[-1,1]\), evaluate \(\ \sin\!\big(2(\sin^{-1}x+\cos^{-1}x)\big)\).
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Key identity: $\sin^{-1}x+\cos^{-1}x=\dfrac{\pi}{2}$ for all $x\in[-1,1]$.
Bihar Board XII - 2023
Bihar Board XII
Updated On:
Oct 17, 2025
\(0\)
\(1\)
\(-1\)
\(1/2\)
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The Correct Option is
A
Solution and Explanation
\(\sin^{-1}x+\cos^{-1}x=\dfrac{\pi}{2}\). Hence \[ 2(\sin^{-1}x+\cos^{-1}x)=2\cdot \frac{\pi}{2}=\pi, \sin(\pi)=0. \]
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