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for x in mathbb r cot 1 x
Question:
For \(x\in\mathbb R\), \(\cot^{-1}x=\ \ ?\)
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$\tan$ and $\cot$ are complementary: swap with $\frac{\pi}{2}-\,$angle.
Bihar Board XII - 2023
Bihar Board XII
Updated On:
Oct 17, 2025
\(\dfrac{\pi}{2}-\sin^{-1}x\)
\(\dfrac{\pi}{2}-\cos^{-1}x\)
\(\dfrac{\pi}{2}-\tan^{-1}x\)
\(\dfrac{\pi}{2}-\sec^{-1}x\)
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The Correct Option is
C
Solution and Explanation
\(\cot\theta=\tan\!\left(\tfrac{\pi}{2}-\theta\right)\). Apply inverse on both sides (with principal ranges): \(\cot^{-1}x=\tfrac{\pi}{2}-\tan^{-1}x\).
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