Question

For which value of \(x\) and \(y\), the following square planar compound shows geometrical isomers \[ [\mathrm{Pt(Cl)_x(Br)_y}]^{2-} \]

• A. \(1,3\)
• B. \(3,1\)
• C. \(2,2\)
• D. \(1,1\)

Hint:

Square planar complexes of type: \[ [\mathrm{MA_2B_2}] \] show: \[ \text{cis-trans geometrical isomerism} \]

Answer 1

The Correct Option is C

Step 1: Recall geometrical isomerism in square planar complexes.
Square planar complexes show geometrical isomerism when: \[ \text{two pairs of identical ligands are present} \] General form: \[ [\mathrm{MA_2B_2}] \] shows: \[ \text{cis and trans isomers} \]

Step 2: Analyze the given complex.
For: \[ [\mathrm{Pt(Cl)_x(Br)_y}]^{2-} \] geometrical isomerism is possible only when: \[ x=2,\qquad y=2 \] Thus complex becomes: \[ [\mathrm{PtCl_2Br_2}]^{2-} \] which shows: \[ \text{cis-trans isomerism} \]

Step 3: Identify the correct option.
Therefore: \[ \boxed{ \mathrm{(C)\ 2,2 } } \]