Divisible by the sum of the square of first n natural numbers
Never divisible by 237
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The Correct Option isD
Solution and Explanation
Expression $n(n+1)(2n+1)$ is always even (two consecutive integers), divisible by 3 (among $n, n+1, 2n+1$ one divisible by 3), and equals $6 \times$ sum of squares of first n naturals. It may be divisible by 237 for some $n$, so (d) is not necessarily true.