
The correct answer is: 10
VB– VA = i × 2
\(=\frac{15}{1+2}\times2\)
\(⇒ \) VB– VA = 10 volts
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,

What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
Electric potential, also known as voltage, is a scalar quantity that measures the amount of electric potential energy per unit charge in an electric field. It is denoted by the symbol V and is measured in volts (V).
The electric potential at a point in an electric field is defined as the amount of work done per unit charge to bring a positive test charge from infinity to that point. The electric potential at a point is also equal to the potential energy per unit charge of a positive test charge placed at that point.
Electric potential is a fundamental concept in electromagnetism and is used to describe the behavior of electric fields and charges. It is also used to calculate the electric potential difference, or voltage, between two points in an electric field.
The electric potential difference between two points is equal to the work done per unit charge to move a positive test charge from one point to the other. The electric potential difference is also equal to the product of the electric field strength and the distance between the two points.
Electric potential has many practical applications, such as in the design and operation of electrical circuits, electric motors, and generators. It is also used in electroplating, electrochemical cells, and other electrochemical processes. Understanding electric potential is crucial for the development and advancement of modern technology.