Step 1: Use Bragg's Law.
\[
n\lambda = 2d\sin\theta
\]
For first-order diffraction: $n = 1$
Step 2: Condition for smallest $d$.
The smallest interplanar spacing $d$ is obtained when $\sin\theta = 1$ (i.e., $\theta = 90^\circ$)
Step 3: Substitute values.
\[
d = \frac{n\lambda}{2\sin\theta} = \frac{1 \times 1.54}{2 \times 1}
\]
\[
d = \frac{1.54}{2} = 0.77 \, \text{\AA}
\]
Step 4: Conclusion.
\[
\boxed{0.77 \, \text{\AA}}
\]