Question:
For decolourisation of 1 mole of KMnO\(_4\), the moles of H\(_2\)O\(_2\) required is:
For decolourisation of 1 mole of KMnO\(_4\), the moles of H\(_2\)O\(_2\) required is:
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For reaction stoichiometry, use the coefficients from the balanced equation to find the mole ratio.
Updated On: Apr 23, 2025
- \( \frac{1}{2} \)
- \( \frac{3}{2} \)
- \( \frac{5}{2} \)
- \( \frac{7}{2} \)
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The Correct Option is C
Solution and Explanation
The reaction for decolourisation of KMnO\(_4\) with H\(_2\)O\(_2\) is: \[ 2KMnO_4 + 3H_2O_2 + 4H_2O \rightarrow 2MnO_2 + 3O_2 + 4KOH \] From the stoichiometry, 3 moles of H\(_2\)O\(_2\) are required for every 2 moles of KMnO\(_4\). Therefore, for 1 mole of KMnO\(_4\), the required moles of H\(_2\)O\(_2\) will be \( \frac{3}{2} \). Thus, the correct answer is Option (C).
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