Question:

For an ideal solution of two components A and B, which of the following is true ?

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In an ideal solution mixing causes no enthalpy or volume change because all intermolecular forces are alike.
Updated On: Nov 11, 2026
  • \(\Delta H_{mixing}\lt0\) (zero)
  • \(\Delta H_{mixing}\gt0\) (zero)
  • A\(-\)B interaction is stronger than A\(-\)A and B\(-\)B interactions
  • A\(-\)A, B\(-\)B and A\(-\)B interactions are identical
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The Correct Option is D

Solution and Explanation

For an ideal solution \(\Delta H_{mixing}=0\) and \(\Delta V_{mixing}=0\).
This happens because the A-B interactions are identical in strength to the A-A and B-B interactions, so Raoult's law is obeyed.
Options (1) and (2) say the enthalpy change is less/greater than zero (not zero), and option (3) describes a negative deviation. Only (4) is true.
Answer: (4) A\(-\)A, B\(-\)B and A\(-\)B interactions are identical
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