Question

For an FM signal with peak frequency deviation of \(50\,\text{kHz}\) and modulating frequency of \(10\,\text{kHz}\), the modulation index is

• A. \(0.2\)
• B. \(2\)
• C. \(5\)
• D. \(10\)

Hint:

For FM, \[ \boxed{ \beta=\frac{\Delta f}{f_m} } \] where \(\Delta f\) is the maximum frequency deviation.

Answer 1

The Correct Option is C

Step 1: Recall the FM modulation index formula. The modulation index is \[ \beta=\frac{\Delta f}{f_m}, \] where - \(\Delta f\) = peak frequency deviation, - \(f_m\) = modulating frequency.

Step 2: Substitute the given values. \[ \beta = \frac{50\,\text{kHz}}{10\,\text{kHz}} = 5. \] Hence, \[ \boxed{5} \] Therefore, \[ \boxed{(C)} \] is the correct answer.